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22 December, 11:34

Given that sin0=21/29 what is the value cos 0 for 0°< 0<90°

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  1. 22 December, 14:32
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    20/29

    Step-by-step explanation:

    sin θ = 21/29

    Use Pythagorean identity:

    sin² θ + cos² θ = 1

    (21/29) ² + cos² θ = 1

    441/841 + cos² θ = 1

    cos² θ = 400/841

    cos θ = ±20/29

    Since 0° < θ 0. So cos θ = 20/29.
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