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13 June, 09:43

The function f/left (x/right) = -/left (x-3/right) ^2+9f (x) = - (x - 3) 2 + 9 can be used to represent the area of a rectangle with a perimeter of 12 units, as a function of the length of the rectangle, xx. What is the maximum area of the rectangle? 12 square units 3 square units 9 square units 6 square units

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  1. 13 June, 13:17
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    9 square units

    Step-by-step explanation:

    The area of the rectangle is f (x) = - (x - 3) ² + 9.

    Since this is a parabola, the maximum is at the vertex, (3, 9).
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