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30 April, 18:27

Given the domain {-4,0,5} what is the range for the relation 12x + 6y=24?

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Answers (2)
  1. 30 April, 21:10
    0
    Answer:The range is (-/frac{1}{12},/frac{1}{15}). The realtion is no defined in 0.
  2. 30 April, 21:42
    0
    {12,4,-6}

    Step-by-step explanation:

    for - 4

    12x+6y=24

    12 (-4) + 6y=24

    -48+6y=24

    +48 + 48

    6y=72

    6 6

    y=12

    for 0

    12x+6y=24

    12 (0) + 6y=24

    6y=24

    6 6

    y=4

    for 5

    12x+6y=24

    12 (5) + 6y=24

    60+6y=24

    -60 - 60

    6y=-36

    6 6

    y=-6
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