Introduction to Solving Word Problems with Algebra - Item 7452Question 1 of 7

A rectangle has a perimeter of 48 feet and a length of 14 feet. Which equation can you solve to find the width?

CLEAR CHECK

2n+28=48

48-n=28

14+n=48

2n+14=48

2n+28=48

2n + 28 = 48

Step-by-step explanation:

- perimeter is 48 ft

- length is 14 ft

formula for perimeter of a rectangle:

P = 2L + 2W

If you substitute in the values we know, then you get:

48 = 2 (14) + 2W

48 = 28 + 2W

W = n, so it's the same as this:

48 = 28 + 2n

And if you switch them around, you get this:

2n + 28 = 48