Which equation can be solved using the expression StartFraction negative 3 plus-or-minus StartRoot (3) squared + 4 (10) (2) EndRoot Over 2 (10) EndFraction for x?

10x2 = 3x + 2

2 = 3x + 10x2

3x = 10x2 - 2

10x2 + 2 = - 3x

Answer: B. 2 = 3x + 10x2

Step-by-step explanation:

This is the concept of quadratic equations; We required to find the type of equation that can be solved using the model that has been used to solve the equation such that the answer is:

[-3+-sqrt (3^2+4 (10) (2)) ] / (2 (10))

The formual that was applied here was a quadratic formula given by:

x=[-b+/-sqrt (b^2-4ac) ]/2a

whereby from the our substituted values above,

a=10, b=3 and c=-2

such that the quadratic equation will be:

10x^2+3x-2

2 = 3x + 10x^2

Step-by-step explanation:

There for the answer is B