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10 May, 11:23

How do i calculate (Log) 23 + (log) 93?

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  1. 10 May, 15:04
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    A property of logs, is

    log ab=log a+log b so

    log 23+log 93=log (23 times 93) = log 2139

    assuming log to base 10 you would be solving for

    10^x=2139

    this is the same as

    log 2139

    not sure how to solve it except by puting it into a calculator or looking it up on a log table

    the answer is aprox 3.3302107845715
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