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31 March, 01:00

If a+b+c=0 for a, b, c then prove a²/bc+b²/ca+c²/ab=3.

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  1. 31 March, 04:57
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    According to the identity if a+b+c=0

    then a3+b3+c3=3abc

    a3+b3+c3/abc=3

    a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3

    cancel a, b, c in all the fraction then you get

    a²/bc+b²/ca+c²/ab=3.

    hence proved
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