When an object is dropped from a building (height 16501650 feet), the object's height, h, in feet, from the ground at time, t, in seconds, after being dropped can be determined by h equals Upper P (t) equals negative 16 t squared plus 1650. h=P (t) = -16t2+1650. Find the distance an object is from the ground 33 seconds after being dropped.

1515 feet

Step-by-step explanation:

The height, h (in feet) of the object from the ground after a given time (t) in seconds is given as:

h=P (t) = -16t²+1650

To determine the height after 3 seconds of an object being dropped, i. e. at t=3

P (t) = -16t²+1650

P (t) = -16 (3) ²+1650

=-16 (9) + 1659

=-144+1659

P (t) = 1515 feet

The height of the object from the ground after 3 seconds is 1515 feet