A jar contains 666 red jelly beans, 444 green jelly beans, and 444 blue jelly beans.

If we choose a jelly bean, then another jelly bean without putting the first one back in the jar, what is the probability that the first jelly bean will be blue and the second will be blue as well?

Question

Cedric Wilkerson

3 November, 05:56

+5

Answers (1)

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Sabrina Reed · Answer 1

Step-by-step explanation:

P (first blue) = 444 / 1554

P (second blue) = 443/1553

P (first blue + second blue) = 444 / 1554 * 443/1553 = 0.08

A jar contains 666 red jelly beans, 444 green jelly beans, and 444 blue jelly beans.If we choose a jelly bean, then another jelly bean without putting the first one back in the jar, what is the probability that the first jelly bean will be blue and the second will be blue as well?