A computer store buys a computer system at a cost of $463.80. The selling price was first at $ 773 , but then the store advertised a 20 % markdown on the system. Answer parts a and b.

a. Find the current sale price.

Question

Mathematics

Porkchop

8 February, 09:13

A computer store buys a computer system at a cost of $463.80. The selling price was first at $ 773 , but then the store advertised a 20 % markdown on the system. Answer parts a and b.

a. Find the current sale price.

+5

Answers (1)

Know the Answer?

Josephine Boyer · Answer 1

Sale prizes:

Part A: 463.80 - 92.76 = $371.04

Part B: 773 - 154.6 = $618.4

Step-by-step explanation:

Formulas used in the calculation:

discount amount/original price = discount%/100%

Sale price = original $ - discount$ = final answer

Part A:

discount amount = x

original price = $463.80

discount amount = 20%

x/463.80 = 20/100

x · 100 = 20 · 463.80

100x = 9,276

100x/100 = 9,276/100

x = $92.76

Part B:

discount amount = x

original price = $773.00

discount amount = 20%

x/773 = 20/100

x · 100 = 20 · 773

100x = 15,460

100x/100 = 15,460/100

x = $154.6

Sale prizes:

Part A: 463.80 - 92.76 = $371.04

Part B: 773 - 154.6 = $618.4

A computer store buys a computer system at a cost of $463.80. The selling price was first at $ 773 , but then the store advertised a 20 % markdown on the system. Answer parts a and b.a. Find the current sale price.

A computer store buys a computer system at a cost of $463.80. The selling price was first at $ 773 , but then the store advertised a 20 % markdown on the system. Answer parts a and b.

a. Find the current sale price.