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Yesterday, 11:30

What is are the steps to factoring - x^2 + 6x - 9

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  1. Yesterday, 12:49
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    Step-by-step explanation:

    -x^2 + 6x - 9

    The first step is to find the coefficient of x^2 (i. e. the num in front of x^2) = - 1

    The constant is - 9

    Therefore, the product of the equation = - 1 x - 9 = + 9

    Sum of the equation = the coefficient of x = + 6

    Then, we look for two factors (numbers) whose product = + 9, and sum = + 6

    What of + 3 and + 3?

    +3 + 3 = + 6

    +3 x + 3 = + 9

    Therefore, + 3 and + 3 are the factors of the equation.

    We then substitute the sum of the equation (+6x) with these factors.

    So, we have,

    -x^2 + 3x + 3x - 9

    We then pair the equation and equate to Zero

    (-x^2 + 3x) (+3x - 9) = 0

    Common factor in the first pair is - x and + 3 in the second.

    -x (x - 3) + 3 (x - 3) = 0

    At this stage, same factor must be in the bracket (i. e. x-3)

    So, we now have,

    (-x + 3) (x-3) = 0

    We equate each to zero

    -x + 3 = 0 and x-3=0

    -x = - 3. and x = + 3

    x = + 3 and x = + 3

    Therefore, x = + 3 and + 3
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