Consider a pyramid with a height 10 feet in a square base with side lengths 7 feet. How does the volume of the pyramid change if the base stays the same and the height is doubled

The volume of a pyramid is given by the formula

V = 1/3 x bxh

b = base, since the base is square, so b = L²=49 feet²

h=10feet

so finally V = 1/3x 49x10 = 163.33 ft^3

if the height is doubled it means H=2h=20

so the volume is V = 1/3x 49x 20=326.33 ft^3