A system of equations is shown below.

5 + 2y = - 15

2x-2y=-6

What is the solution to the system of equations?

A

B

C

D

(-3,0)

(0,-3)

(-3,6)

(6,-3)

You can use the process elimination to solve. In other words, subtract or add the equations like normal.

5x + 2y = - 15

+ 2x - 2y = - 6

Because there is a 2y and - 2y, we can add both equations to eliminate the y so that we can figure out what x is:

5x + 2x = 7x

2y + (-2y) = 0

-15 + (-6) = - 21

We now have 7x = - 21

Divide all by 7 to get x = - 3

Plug in - 3 to any of the two equations. I will use the second equation:

2 (-3) - 2y = - 6

-6 - 2y = - 6

-2y = 0

y = 0

This means that the solution to the system of equations is (-3, 0) in the form of (x, y).