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Today, 18:08

6.

The school that Laura goes to is selling tickets to the annual talent show. On the first day of

ticket sales the school sold 4 senior citizen tickets, 2 adult tickets and 5 child tickets for a total of

$55. The school took in $67 on the second day by selling 7 senior citizen tickets, 2 adult tickets

and 5 child tickets. On the third day the show earned $46 when they sold 2 senior citizen tickets,

4 adult tickets and 2 child tickets. What is the price each of one senior citizen ticket, one adult

ticket and one child ticket?

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Answers (1)
  1. Today, 19:25
    0
    The price of 1 senior citizen ticket is $4

    The price of 1 adult ticket is $7

    The price of 1 child ticket is $5

    Step-by-step explanation:

    Assume that the costs of a senior ticket is $x, an adult ticket is $y and

    a child ticket is $z

    First day:

    The school sold 4 senior citizen tickets, 2 adult tickets and 5 child

    tickets for a total of $55

    ∴ 4x + 2y + 5z = 55 ⇒ (1)

    Second day:

    The school sold 7 senior citizen tickets, 2 adult tickets and 5 child

    tickets for $67

    ∴ 7x + 2y + 5z = 67 ⇒ (2)

    Third day:

    The school sold 2 senior citizen tickets, 4 adult tickets and 2 child

    tickets for $46

    ∴ 2x + 4y + 2z = 46 ⇒ (3)

    The number of adult tickets and the number of child tickets in the first

    and second days are equal, then we can subtract equation (1) from

    equation (2) to find x

    Subtract equation (1) from equation (2)

    ∴ (7x - 4x) + (2y - 2y) + (5z - 5z) = 67 - 55

    ∴ 3x = 12

    Divide both sides by 3

    ∴ x = 4

    Substitute the value of x in equation (2)

    ∴ 7 (4) + 2y + 5z = 67

    ∴ 28 + 2y + 5z = 67

    Subtract 28 from both sides

    ∴ 2y + 5z = 39 ⇒ (4)

    Substitute the value of x in equation (3)

    ∴ 2 (4) + 4y + 2z = 46

    ∴ 8 + 4y + 2z = 46

    Subtract 8 from both sides

    ∴ 4y + 2z = 38 ⇒ (5)

    Now lets solve equations (4) and (5) to find y and z

    Multiply equation (4) by - 2 to eliminate y

    ∴ - 4y - 10z = - 78 ⇒ (6)

    Add equations (5) and (6)

    ∴ - 8z = - 40

    Divide both sides by - 8

    ∴ z = 5

    Substitute the value of z in equation (4) or (5)

    ∴ 2y + 5 (5) = 39

    ∴ 2y + 25 = 39

    Subtract 25 from both sides

    ∴ 2y = 14

    Divide both sides by 2

    ∴ y = 7

    The price of 1 senior citizen ticket is $4

    The price of 1 adult ticket is $7

    The price of 1 child ticket is $5
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