When dividing the polynomial p (1) = 4t^3 - 17t^2 + 14t - 3 by t - 3, the remainder can be determined by evaluating p (3). What is the value of this

remainder?

A P (3) = - 27

B. P (3) = - 6

C. P (3) = 0

D. p (3) = 45

Question

Mathematics

Guest

24 February, 19:08

When dividing the polynomial p (1) = 4t^3 - 17t^2 + 14t - 3 by t - 3, the remainder can be determined by evaluating p (3). What is the value of this

remainder?

A P (3) = - 27

B. P (3) = - 6

C. P (3) = 0

D. p (3) = 45

+4

Answers (1)

Know the Answer?

Deon Travis · Answer 1

The answer to your question is the letter B. P (3) = - 6

Step-by-step explanation:

4t² - 5t - 1

t - 3 4t³ - 17t² + 14t - 3

-4t³ + 12t²

0 - 5t² + 14t

+5t² - 15t

0 - t - 3

+t - 3

0 - 6

Quotient = 4t² - 5t - 1

Remainder = - 6

The remainder is constant it always be - 6

P (3) = 4 (3) ³ - 17 (3) ² + 14 (3) - 3

= 4 (27) - 17 (9) + 42 - 3

= 108 - 153 + 42 - 3

= 150 - 156

= - 6

When dividing the polynomial p (1) = 4t^3 - 17t^2 + 14t - 3 by t - 3, the remainder can be determined by evaluating p (3). What is the value of thisremainder?A P (3) = - 27B. P (3) = - 6C. P (3) = 0D. p (3) = 45

When dividing the polynomial p (1) = 4t^3 - 17t^2 + 14t - 3 by t - 3, the remainder can be determined by evaluating p (3). What is the value of this

remainder?

A P (3) = - 27

B. P (3) = - 6

C. P (3) = 0

D. p (3) = 45