A company sells apples in packages of 444. The masses of the individual apples are normally distributed with a mean of 175/,/text{g}175g175, start text, g, end text and a standard deviation of 15/,/text{g}15g15, start text, g, end text. Assume that the weights of apples are independent from each other.

Answer: let the probability of weights less than 160 be the required value, then, using z-score formula

z-score = (x - ∪) : Ф where, x is 160, ∪ is population mean = 175,

Ф is the population standard deviation = 15

z-score = (160 - 175) : 15 = - 1

p (z< - 1) = 0.159

Step-by-step explanation:

the question is not complete. Assuming that the missing figure is 160 representing the required weights ess than the normal weights of 175.

step 1. obtain the z-score value by using the formula

z = (x - ∪) : Ф

step 2. obtain the probability of weights less than 160 from normal distribution table. since z-score value is - 1, the probability is obtained as 0.159 that is 15.9%