Use substitution: y = x + 1 2y = 3x Use elimination: 2x + 3y = 20

-2x + y = 4

Question 1

X=0, y=0

Question 2

x=1, y=6

Step-by-step explanation:

The first question says we should solve by using substitution

y=3x ... (1)

X+12y=3x ... (2)

Let's substitute (1) into (2)

X+12 (3x) = 3x

X+36x=3x

Let's collect like terms

X+36x-3x=0

34x=0

Divide both sides by 34

X=0

Let's substitute the value of x in (1)

y=3 (0)

y=0

Therefore x=0, y=0

The other question is elimination

2x+3y=20 ... (1)

-2x+y=4 ... (2)

Add (1) and (2)

4y=24

Let's make y the subject of formula by dividing both sides by 4

y=6

Substitute the value of y into (2)

-2x+6=4

Collect like terms

-2x=4-6

-2x=-2

Divide both sides by 2

x=1

Therefore x=1, y=6