How do i solve 5x+3y=-10 & 3x+5y=-6

Solve it using elimination method:

5x+3y=-10

3x+5y=-6

Essentially what you would want to do is eliminate a variable so you have to multiply the two equations so that the two "y"s cancel each other out. You do this by multiplying one by a negative number and the other one a positive number. Doesn't matter what number you multiply the number with; however, both numbers need to be the same distance away from zero. Also, if you're going to multiply one term, then all the terms will need to be multiplied.

-5 (5x+3y) = -10

3 (3x+5y) = -6

Distribute and Multiply:

-25x-15y=50

9x+15y=-18

Now add the two equations by adding the x's together, y's, and the total.

The y's end up canceling each other.

-16x=32

Divide:

X=-2

Now that you have "X" substitute x from one of the equations from the beginning. You may do two for checking answers.

3 (-2) + 5y=-6

-6+5y=-6

5y=0

Y=0

The answer is:

x=-2

y=0

(-2,0)