Ask Question
31 December, 21:35

Mr. Jones has 10 books that he is going to put on his bookshelf. Of these, 4 are mathematics books, 3 are chemistry books, 2 are history books, and 1 is a language book. Jones wants to arrange his books so that all the books dealing with same subject are together on the shelf. How many different arrangements are possible?

+2
Answers (1)
  1. 31 December, 23:25
    0
    Step-by-step explanation:

    We consider 4 math books as one unit, 3 chemistry books as one unit and 2 history books as one unit and 1 language book as another unit (He wants to arrange his books so that all books dealing with same subject are together on the shelf)

    Number of different arrangements possible = number of arrangements of 4 objects = 4! = 4 * 3 * 2 * 1 = 24
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Mr. Jones has 10 books that he is going to put on his bookshelf. Of these, 4 are mathematics books, 3 are chemistry books, 2 are history ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers