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19 February, 11:22

Abdul will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of and costs an additional per mile driven. The second plan has an initial fee of and costs an additional per mile driven. How many miles would Abdul need to drive for the two plans to cost the same?

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  1. 19 February, 14:36
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    The question is missing some important details required to answer the question. I found a similar question, so I will answer using this details. If there is any differences in the details, you can still use my working by changing the value given:

    Abdul will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $38 and costs an idditional $0.11 per mile driven. The second plan has an initial fee of $49 and costs an additional $0.07 per mile driven.

    How many miles would Abdul need to drive for the two plans to cost the same?

    Answer:

    275 miles

    Step-by-step explanation:

    Let the distance travel be X

    First plan:

    Initial fee: 38

    Per mile: 0.11

    So the total cost is

    C1 = 38 + 0.11X

    Second plan:

    Initial fee: 49

    Per mile:0.07

    So the total cost is

    C2 = 49 + 0.07X

    Since the question asked about when the total cost be the same, we can say that C1 = C2

    C1 = C2

    38 + 0.11X = 49 + 0.07X

    0.11X - 0.07X = 49 - 38

    0.04X = 11

    X = 11/0.04 = 275

    At 275 miles, the cost will be the same.
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