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11 November, 08:34

A box is dragged 16 m across a level floor by a 25-N force at an angle of 45° to the floor. It is then dragged by

the same force 7 m up a ramp inclined at an angle of 10° to the floor. Determine the total work done by the

force.

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Answers (1)
  1. 11 November, 09:23
    0
    solution

    W=f*d*cos theta

    =25N*16m*cos 45°

    =400Nm*cos 45°

    =282.84J

    W=f*d*cos theta

    =25N*7m*cos 10°

    =175Nm*cos10°

    =172.34J

    Total workdone=282.84J+172.34J=455.18J
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