Ask Question
26 April, 10:21

Two boys divided $3.36 so that one boy received 12 cents less than three times as much as the other. How was the money divided?

+3
Answers (2)
  1. 26 April, 12:56
    0
    x + y = 3.36 - -> the boys are splitting $3.36

    x = 3y -.12 - -> one boy received $.12 less than 3 times as much as the other

    --> substitute the second equation for the x in the first equation

    (3y -.12) + y = 3.36 - -> combine like terms

    4y -.12 = 3.36 - -> add. 12 to both sides of the equation

    4y = 3.48 - -> divide both sides by 4

    y =.87

    the other boy gets $0.87

    substitute into x = 3y - 12

    x = 3 (.87) -.12

    x = 2.61 -.12

    x = 2.49

    the first boy gets $2.49
  2. 26 April, 13:15
    0
    first one take 1.5$ and the second one take 1.86$
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Two boys divided $3.36 so that one boy received 12 cents less than three times as much as the other. How was the money divided? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers