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29 March, 03:09

Given the functions f (x) = 2x2 - 8x, g (x) = x2 - 6x 1, and h (x) = - 2x2, rank them from least to greatest based on their axis of symmetry.

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  1. C
    29 March, 03:49
    0
    If you have a quadratic equation y = ax² + bx + c

    Where a, b, and c are constants.

    The axis of symmetry is: x = - b/2a

    For f (x) = 2x² - 8x, comparing a=2, b = - 8, c = 0

    x = - b/2a = - (-8) / (2*2) = 8/4 = 2. Axis of symmetry or line of symmetry is x = 2

    For g (x) = x² - 6x + 1, comparing a=1, b = - 6, c = 1. (Note am taking the last term as + 1, it still does not affect the answer if it is otherwise)

    x = - b/2a = - (-6) / (2*1) = 6/2 = 3. Axis of symmetry or line of symmetry is x = 3

    For h (x) = - 2x² comparing a=-2, b = 0, c = 0

    x = - b/2a = - (0) / (2*-2) = 0/-4 = 0. Axis of symmetry or line of symmetry is x = 0

    Ranking the axis of symmetry or line of symmetry from the least to the greatest:

    x = 0, 2, 3 That is:

    h (x), f (x), & g (x)
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