solve this word problem leading to quadratic equation: the area of a rectangle is 60cm². The length is 11cm more than the width. Find the width.

Step-by-step explanation:

let : x The length and y the width you have this system:

xy = 60 ... (1)

x = y+10 ... (2)

put the value for x in (1) : (y+10) y = 60

the quadratic equation is : y² + 10y - 60 = 0

Δ = b² - 4ac a = 1 b = 10 c = - 60

Δ = 10² - 4 (1) (-60) = 324 = 18²

y 1 = (-10-18) / 2 negatif ... refused

y 2 = (-10+18) / 2 = 4

the width is 4