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18 November, 11:43

Find all of the zeros of the function and write the polynomial as the product of linear factors.

h (x) = x^3+x^2+36x+36

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  1. 18 November, 13:25
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    (x+6i) (x-6i) (x+1)

    So the zeroes are 6i, - 6i, - 1

    Step-by-step explanation:

    Factor by grouping

    h (x) = x^2 (x+1) + 36 (x+1)

    h (x) = (x^2+36) (x+1)
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