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31 March, 12:46

In an emergency, a driver brings a car to stop in 8.0 s. The car was going 21 m/s when the braking began. What was the stopping distance

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  1. 31 March, 14:37
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    84 m.

    Step-by-step explanation:

    Use an equation of motion under constant acceleration:

    initial speed u = 21, final speed v = 0, time t = 8, distance s = ?.

    s = (u + v) t / 2

    = (21 + 0) * 8 / 2

    = 168 / 2

    = 84 m
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