What is the energy stored in a spring when it is compressed 5mm by a 60N force?

Answer: 0.15J

Step-by-step explanation:

Fom th question, we obtained the following information:

F = 60N

e = 5mm

We need to covert 5mm to m

1mm = 0.001m

5mm = 5 x 0.001 = 0.005m

We need to find the spring constant (K) for the spring. This is illustrated below:

K = F / e

K = 60 / 0.005 = 12000N/m

Now we can obtain the energy stored on the spring by the doing following:

Energy = 1/2 Ke^2

Energy = 1/2 x 12000 x (0.005) ^2

Energy = 0.15J

can you elaborate?