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15 June, 03:02

10x+4y + 12z=120

11x + 77y = 220

8x + 2y + 32z = 160

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Answers (1)
  1. 15 June, 04:25
    0
    x=8.94; y = 1.58; z=2.02

    Step-by-step explanation:

    solve 10x+4y+12z = 120 → 5x+2y+6z = 60

    8x + 2y + 32Z = 160 → 4x+y+16z = 80

    To eliminate z multiply first equation by 16 and second equation by 6.

    80x+32y+96z = 960

    24x+6y+96z = 480

    on subtractionwe get 56x+26y = 480

    dividing by 2 we get, 28x + 13y = 240

    Now we have a given equation 11x + 77y = 220 → x + 7y = 20

    solving 28x + 13y = 240 and x + 7y = 20

    28x + 13y = 240

    28x + 216y = 560

    subtracting we get, 203y = 320

    y = 1.58

    x = 8.94

    z = 2.02
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