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7 January, 06:01

On commencing employment a man is paid a salary of $7200 per annum and receives annual increments of $350. Determine his salary in the 9th year and calculate the total he will have in the first 12years.

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  1. 7 January, 07:17
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    Step-by-step explanation:

    From the question, we can form an equation like: S = 7200 + 350X

    where S is the salary and X is year.

    1. His salary in the 9th year, means X=9, so we substitute 9 into the equation to find S = 7200 + 350 (9) = 10350

    2. The total he will have in the first 12years, we have:

    Sum of first n terms of an AP: S = (n/2) [2a + (n - 1) d] where a is the value of the 1st term, here a is 7200 and d = 350 the common difference between terms

    => S = (12/2) [2*7200 + (12 - 1) 350] = 109500
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