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8 January, 09:02

An investment is worth $3 comma 659 in 1992. By 1997 it has grown to $ 6 comma 659. Let y be the value of the investment in the year x, where xequals0 represents 1992. Write a linear equation that models the value of the investment in the year x.

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  1. 8 January, 11:36
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    y = 600x + 3659

    Step-by-step explanation:

    General form of the linear equation:

    y = mx + b

    Given:

    x = 0 represents 1992

    x = 0, y = 3659

    So, x value for 1997 becomes:

    x = 1997-1992 = 5

    at x = 5, y = 6659

    Plugging in x = 0, y = 3659 in y = mx+b

    3659 = m (0) + b

    b = 3659

    Plugging in x = 5, y = 6659 and b = 3659

    6659 = m (5) + 3659

    Solving for m:

    m (5) = 6659-3659

    5m = 3000

    m = 3000/5 = 600

    Now plug in the values of unknowns m and b in general equation:

    y = 600x + 3659
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