Ask Question
16 February, 10:38

The area of a rectangle is 81x^10y^2. If the length of the rectangle is 3x^6y^-4, find the width

+5
Answers (1)
  1. 16 February, 14:24
    0
    width = (27x⁴) (10y⁶)

    Step-by-step explanation:

    Multiplying numbers will multiply their coefficient. For 3x, 3 must multiply with another number to get 81. That number is 27, so 3x (27) = (3⋅27) x = 81x.

    Now you need the power.

    Multiplying numbers with the same base will add up their exponent. I got x⁶ but need to get to x¹⁰.

    Just multiply it by x⁴ so that you get (x⁶) (x⁴) = x⁶⁺⁴ = x¹⁰.

    Do the same for y.

    A = LW

    (81x¹⁰) (10y²) = (3x⁶) (y⁻⁴) (W)

    (81x¹⁰) (10y²) = (3x⁶) (y⁻⁴) (27x⁴) (10y⁶)

    (81x¹⁰) (10y²) = (3x⁶) (27x⁴) (y⁻⁴) (10y⁶)

    (81x¹⁰) (10y²) = (3⋅27x⁶⁺⁴) (y⋅10⁻⁴⁺⁶)

    (81x¹⁰) (10y²) = (81x¹⁰) (10y²)

    width = (27x⁴) (10y⁶)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The area of a rectangle is 81x^10y^2. If the length of the rectangle is 3x^6y^-4, find the width ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers