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3 September, 14:13

How many solutions does the equation 3 (x+2) - 10=4x-6+x have?

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Answers (2)
  1. 3 September, 15:03
    0
    Answer: The answer is 1

    Step-by-step explanation:

    Simplifying

    3 (x + 2) + - 10 = 4x + - 6 + x

    Reorder the terms:

    3 (2 + x) + - 10 = 4x + - 6 + x

    (2 * 3 + x * 3) + - 10 = 4x + - 6 + x

    (6 + 3x) + - 10 = 4x + - 6 + x

    Reorder the terms:

    6 + - 10 + 3x = 4x + - 6 + x

    Combine like terms: 6 + - 10 = - 4

    -4 + 3x = 4x + - 6 + x

    Reorder the terms:

    -4 + 3x = - 6 + 4x + x

    Combine like terms: 4x + x = 5x

    -4 + 3x = - 6 + 5x

    Solving

    -4 + 3x = - 6 + 5x

    Solving for variable 'x'.

    Move all terms containing x to the left, all other terms to the right.

    Add '-5x' to each side of the equation.

    -4 + 3x + - 5x = - 6 + 5x + - 5x

    Combine like terms: 3x + - 5x = - 2x

    -4 + - 2x = - 6 + 5x + - 5x

    Combine like terms: 5x + - 5x = 0

    -4 + - 2x = - 6 + 0

    -4 + - 2x = - 6

    Add '4' to each side of the equation.

    -4 + 4 + - 2x = - 6 + 4

    Combine like terms: - 4 + 4 = 0

    0 + - 2x = - 6 + 4

    -2x = - 6 + 4

    Combine like terms: - 6 + 4 = - 2

    -2x = - 2

    Divide each side by '-2'.

    x = 1

    Simplifying

    x = 1
  2. 3 September, 17:30
    0
    x=1

    Step-by-step explanation:

    3 (x+2) - 10=4x-6+x

    3x+6-10=5x-6

    3x-5x-4=-6

    -2x-4=-6

    -2x=-6+4

    -2x=-2

    2x=2

    x=2/2

    x=1
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