Given the coordinates of the vertices of a quadrilateral, determine whether it is a square, a rectangle, or a parallelogram. Then find the perimeter of the quadrilateral. A (6, - 4), B (11, - 4), C (11, 6), D (6, 6)

The answer to your question is: it's a rectangle

perimeter = 30 u

Step-by-step explanation:

d = √ ((x2. x1) ² + (y2-y1) ²)

Now, calculate the distances AB, BC, CD, AD

dAB = √ ((11-6) ² + (-4+4) ² = √5² = 5

dBC = √ ((11-11) ² + (-4-6) ² = √10 = 10

dCD = √ ((6-11) ² + (6-6) ² = √5² = 5

dAD = √ ((6-6) ² + (6+4) ² = √10² = 10

From the results we conclude that is a rectangle because two sides have the same length and the other two also measure the same. We can draw it to confirm this.

Perimeter = dAB + dBC + dCD + dAD

= 5 + 10 + 5 + 10 = 30 units