The College Board reports that 2% of the two million high school students who take the SAT each year receive special accommodations because of documented disabilities (Los Angeles Times, July 16, 2002). Consider a random sample of 25 students who have recently taken the test. a. What is the probability that exactly 1 received a special accommodation

the probability that exactly 1 received a special accommodation is 0.3079

Step-by-step explanation:

Step 1: define the variable

x = the number of students who received a special accommodation.

Step 2: define the distribution of this variable

x ~ binomial distribution (p=0.02, n=25)

this is because x is the number of succes in 25 trials.

Step 3: using the binomial distribution formula

P (x=1) = (25C1) * (0.05^1) * (1-0.05) ^ (25-1) = 0.3079

where (25C1) is a combination