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17 March, 01:23

A turboprop plane flying with the wind flew 400 mi in 4 h. Flying against the wind, the plane required 5 h to travel the same distance. Find the rate of the plane in calm air and the rate of the wind.

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  1. 17 March, 01:37
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    Rate of the plane in calm air is 90 miles/hr and rate of the wind of wind is 10 miles/hr

    Step-by-step explanation:

    Average speed of plane in with wind = 400 / 4 = 100 miles/hr

    Average speed of plane against wind = 400/5 = 80 miles/hr

    Consider the speed of plane in wind be x miles/hr and speed of plane against wind be y miles/hr

    As such speed of plane in wind would be x + y miles/hr and speed of plane against wind would be x - y miles/hr. i. e

    x+y = 100

    x-y = 80

    by solving these two equation, we get

    2x=180

    x = 90 miles/hr

    y=100-90

    y = 10 miles/hr

    hence, Rate of the plane in calm air is 90 miles/hr and rate of the wind of wind is 10 miles/hr
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