4[z + 3 (Z - 1) ] = 36

How do you solve this problem?

4z+2 (square) 2z=2 (square) 6

Step-by-step explanation:

4 ((z+3 (z-1))) = 36

4 (z^2-z+3 ((z-3))) = 36

4 (z^2-z+3z-3) = 36

4 ((z^2 + (-z+3z) - 3)) = 36

4 (z^2+2z-3) = 36

4z^2+8z-12=36

4z^2+8z=24

((4 (square) z^2)) + (square) 8z = (square) 24

4z+2 (square) 2z=2 (square) 6

3

Step-by-step explanation:

4[z+3 (z-1) ]=36

z+3 (z-1) = 36/4

z+3z-3=9

4z-3=9

4z=9+3

4z=12

z=12/4

z=3