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13 September, 16:34

What is the constant of proportionality for the ratios; (2,3), (4,6), (6,9) and (8,12)

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  1. 13 September, 19:46
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    Step-by-step explanation:

    The constant of proportionality is equal to the change in x/the change in y.

    Change in x is equal to the second x value minus the first x value, and same for y.

    Let's take (2,3), and (4,6).

    The second x value is 4 and the first x value is 2. 4-2=2, so the change in x = 2

    The second y value is 6 and the first y value is 3. 6-3=3, so the change in y = 3

    Now that we know the change in x and the change in y, we can plug it in to our formula from before.

    2 (change in x) : 3 (change in y) is 2/3.

    The constant of proportionality is 2/3.
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