Ask Question
10 June, 11:58

A group of 6 men and 6 women is randomly divided into 2 groups of size 6 each. What is the probability that both groups will have the same number of men?

+3
Answers (2)
  1. 10 June, 12:15
    0
    0. 4329

    Step by step explanation

    Since both groups will have the same number of men, we would guarantee each group consists of three women and three men.

    So theprobability is (6, 3) · (6, 3) / (12, 6) = 100/231.
  2. 10 June, 12:34
    0
    P (A) = 400/924 = 100/231 or 0.4329

    Step-by-step explanation:

    The probability that both groups will have the same number of men P (A);

    For the two groups to have the same number of men they must include 3 men and 3 women in each group.

    P (A) = Number of possible selections of 3 men from 6 and 3 women from 6 into each of the two groups N (S) : total number of possible selections of members into the two groups N (T).

    P (A) = N (S) / N (T)

    Since order is not important, we will use combination.

    N (S) = 6C3 * 6C3 = 20 * 20 = 400

    N (T) = 12C6 = 924

    P (A) = 400/924 = 100/231 or 0.4329
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A group of 6 men and 6 women is randomly divided into 2 groups of size 6 each. What is the probability that both groups will have the same ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers