The area of the rectangle is 3x2+6x-12square units. The length is x2+2x-4 What is the width of the rectangle?

delete for question misunderstood

width (w) = 3

Step-by-step explanation:

The Area of a Rectangle = l * w

Where

l = length

w = width

From the question,

Area (A) = 3x²+6x-12

Length (l) = x² + 2x - 4

To solve for width, let's rearrange the area.

A = 3x²+6x-12

A = 3 (x² + 2x - 4)

From (A = lw)

Let's substitute the values:

3 (x² + 2x - 4) = w * x² + 2x - 4

Divide both sides by (x² + 2x - 4)

3 = w.

Therefore, width (w) = 3