Mike and Joey bought identical loaves of bread and packages of bologna. Mike made sandwiches with 5 slices of bologna and had 4 slices of bread left when he ran out of meat. Joey made sandwiches with 4 slices of bologna and had 4 slices of meat when he ran out of bread. How many slices of bread were in each loaf?

The correct answer is 28 slices of bread

Step-by-step explanation:

Let there be BO slices of bologna and BR slices of bread in a package.

Mike use BO/5 (5 slides per sandwich) and he use bread, BR - 4 = BO/5 x2

Joey use (BO-4) / 4 and BR = (BO-4) / 4 x2

We know BO and BR are the same for each one, so we can replace BR in one equation and Isolate BO

((BO-4) / 4 x2) - 4 = BO/5 x2

We divide each term by 2

((BO-4) / 4) - 2 = BO/5

BO/4-1 - 2=BO/5

BO/4-3=BO/5

BO/4 - BO/5=3

5BO-4BO/20=3

1BO/20=3

BO = 3x 20

BO=60

and BR = (BO-4) / 4 x2

BR = (60-4) / 4 x2

BR = (56) / 4 x2

BR=14 x 2 = 28

Mike had 14 slice of bread in his loaf while

Joey had 8 slice of bread in his loaf.

Step-by-step explanation:

We should note that a sandwich is made up of two slice of bread.

that is:

A Sandwich = 2 Slice of bread

and for bologna to be in a sandwich, you will have 2 slice of bread together.

So, For Mike,

2 slice of bread * 5 Sandwich = 10 Slice of bread

Remaining Slice of bread = 4 Slice

Total Slice of bread in Mike loaf = 10 + 4

= 14 slice of bread was in Mike loaf of bread.

For Joey

A sandwich = 2 Slice of bread

2 slice of bread * 4 Sandwich = 8 Slice of bread

Remaining slice of bread = 0

Total slice of bread in joey loaf = 8 slice of bread.