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9 January, 18:53

If a polygon has 189 diagonals how many sides does the polygon have?

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Answers (2)
  1. 9 January, 20:32
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    N (n-3) / 2=189

    n (n-3) = 378

    n^2-3n-378=0

    n=21
  2. 9 January, 20:39
    0
    (n take 2) minus n = 189

    n (n-3) / 2 = 189

    n (n-3) = 378

    n^2-3n-378 = 0

    n=21
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