The function A (s) given by A (s) equals0.328splus50 can be used to estimate the average age of employees of a company in the years 1981 to 2009. Let A (s) be the average age of an employee, and s be the number of years since 1981; that is, sequals0 for 1981 and sequals9 for 1990. What was the average age of the employees in 2003 and in 2009?

Average age of the employees in 2003 = 57.216 Average age of the employees in 2009 = 59.184

Step-by-step explanation:

We are given the function A (s) as;

A (s) = 0.328*s + 50 where s = number of years since 1981; that is,

s = 0 for 1981 and s = 9 for 1990

A (s) = the average age of an employee

Now, the average age of the employees in 2003, A (22) = 0.328*22 + 50

Here s = 22 because 2003 - 1981 = 22 years

Therefore, average age of the employees in 2003 = 7.216 + 50 = 57.216.

Average age of the employees in 2009, A (28) = 0.328*28 + 50

Here, s = 28 because 2009 - 1981 = 28 years

Therefore, average age of the employees in 2009 = 9.184 + 50 = 59.184.