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24 February, 12:16

Factorize: (2a+3b) the whole square-16c square

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Answers (2)
  1. 24 February, 13:12
    0
    (2a+3b) ² - (16c) ² = (2a + 3b - 16c) * (2a + 3b + 16c)

    Step-by-step explanation:

    (2a+3b) ² - (16c) ² = [ (2a+3b) - 16c]*[ (2a+3b) + 16c]

    = [2a + 3b - 16c]*[2a + 3b + 16c]
  2. 24 February, 14:53
    0
    Step-by-step explanation:

    hello:

    (2a+3b) ² - (16c) ² = [ (2a+3b) - 16c]*[ (2a+3b) + 16c]

    = [2a + 3b - 16c]*[2a + 3b + 16c]

    by identity : x² - y² = (x-y) (x+y) when x = 2a+3b and y = 16c
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