The length of a rectangle is 2 units more than the width. The area is 63 units. What is the width, in units, of the rectangle?

First, let's write what the question says in equation form:

(The length of a rectangle is 2 units more than the width)

L = w + 2

(The area is 63 units)

L * w = 63

Since we already know the value of L ('w + 2'), we can simply input that into the equation to solve for area:

L * w = 63

(w + 2) * w = 63

w^2 + 2w = 63

Subtract both sides by 63:

w^2 + 2w - 63 = 0

Factor:

(w + 9) (w - 7) = 0

We get two answers:

{-9, 7}

Since the width can't be negative, the only possible answer is 7.

w = 7

We can input 'w' into the first equation:

L = 7 + 2

L = 9

The width is 7 units, and the length is 9 units,

-T. B.