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27 February, 23:29

The position of the particle moving in space at time t ≥ 0 is r (t) = (2 + 2 cos (t)) i - 2 sin (t) j + (3 - t π) k. Find the first time moment t0 such that the velocity vector v (t0) is orthogonal to the vector i - j.

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  1. 27 February, 23:53
    0
    t0 = π/4

    Step-by-step explanation:

    The velocity v (t) = r' (t) =

    Since ⊥v, •v=0. So,

    (1) (-2sint) + (-1) (-2cost) = 0

    cost - sint = 0
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Home » Mathematics » The position of the particle moving in space at time t ≥ 0 is r (t) = (2 + 2 cos (t)) i - 2 sin (t) j + (3 - t π) k. Find the first time moment t0 such that the velocity vector v (t0) is orthogonal to the vector i - j.
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