A ball is thrown vertically upward from ground level with an initial velocity of 80 feet per second. The ball's h height after t seconds is given by the equation h = - 16t2 + 80t. How long will it take for the ball to hit the ground?

Question

Mathematics

Diya Wilkerson

1 May, 16:16

A ball is thrown vertically upward from ground level with an initial velocity of 80 feet per second. The ball's h height after t seconds is given by the equation h = - 16t2 + 80t. How long will it take for the ball to hit the ground?

+1

Answers (2)

Know the Answer?

Aron Porter · Answer 1

A

Step-by-step explanation:

It only takes 5 seconds friend.

Demarcus Price · Answer 2

The ball will take 5 seconds to hit the ground.

Step-by-step explanation:

The ball's h height after t seconds is given by the equation h = - 16t² + 80t

When the ball hit the ground, the height will be zero.

∴ h = - 16t² + 80t = 0

∴ - 16t² + 80t = 0 take t as common

t (-16t + 80) = 0

∴ t = 0 Or - 16t + 80 = 0

-16t + 80 = 0

-16t = - 80

t = - 80/-16 = 5 seconds

So, The ball will take 5 seconds to hit the ground.