The sum of 4 consecutive integers is 18

Answer: 3, 4, 5 and 6

Step-by-step explanation:

Let the consecutive integers be; x, x+1, x + 2 and x + 3, then their sum implies:

x + (x + 1) + (x + 2) + (x + 3) = 18

x + x + 1 + x + 2 + x + 3 = 18

4x + 6 = 18

4x = 18 - 6

4x = 12

x = 3

Therefore, the numbers are

3, 3 + 1, 3 + 2 and 3 + 3

which are:

3, 4, 5, 6