Three consecutive even integers have a sum of 18. Find the integers.

Let

x = first consecutive even

x + 2 = second consecutive even

x + 4 = third consecutive even

Based on the problem, we equate

x + (x + 2) + (x + 4) = 18

Solving for x,

3x + 6 = 18

3x = 18 - 6

3x = 12

x = 12/3

x = 4

and x + 2 = 4 + 2 = 6

and x + 4 = 4 + 4 = 8

Therefore, the three consecutive even integers are 4, 6, 8.