A bag contains 222 red marbles, 222 green marbles, and 444 blue marbles.

If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be red and the second will be green?

Question

Mathematics

Gracelyn Crane

19 April, 13:29

A bag contains 222 red marbles, 222 green marbles, and 444 blue marbles.

If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be red and the second will be green?

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Answers (1)

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Spunky · Answer 1

1/14

Step-by-step explanation:

Assuming you mean that there are 2 red, 2 green, and 4 blue marbles, there are a total of 8 marbles.

On the first draw, the probability the marble is red is 2/8.

On the second draw, there's one less marble, so the probability of selecting a green marble is 2/7.

The total probability is:

2/8 * 2/7 = 1/14

A bag contains 222 red marbles, 222 green marbles, and 444 blue marbles.If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be red and the second will be green?

A bag contains 222 red marbles, 222 green marbles, and 444 blue marbles.

If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be red and the second will be green?