6. The mean of 5 consecutive integers is 19. What is the difference between the largest and

the smallest of the 5 integers?

4

Step-by-step explanation:

The integers are

x

x+1

x+2

x+3

x+4

since they are consecutive

The largest is x+4

The smallest is x

Difference is

x+4 - x

4

Step-by-step explanation:

If the least integer is n, it means the five consecutive integers are:

n, n+1, n+2, n+3, n+4

Summing all integers we have:

n + n+1+n+2+n+3+n+4

=5n+10

The mean of this integers is

5n+10 / 5 = 19

5n+10=19*5

5n + 10 = 95

5n = 95 - 10

5n = 85

n=85/5=17

The smallest of the integer is n = 17

The largest integer is n + 4 = 17+4=23

The difference between the least and largest integer would be;

Is 4

The sum of largest integer and the smallest integer is 23 + 17 = 40